2x^2-36x+8=0

Solution for 2x^2-36x+8=0 equation:

2x^2-36x+8=0

a = 2; b = -36; c = +8;
Δ = b2-4ac
Δ = -362-4·2·8
Δ = 1232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1232}=\sqrt{16*77}=\sqrt{16}*\sqrt{77}=4\sqrt{77}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{77}}{2*2}=\frac{36-4\sqrt{77}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{77}}{2*2}=\frac{36+4\sqrt{77}}{4}
$